My Friends,

YoElMiCrO and Vidura's work, to understand Fighter's work, is very important!

Lets take the following Experiment:

A Single loop of wire, the length of a single loop is: 111mm and we have 100 loops the same length.

Our 100 loops at 111mm each is equal to **N1**.

Our equation:

N2 = SQR (n) N1

Ref: YoElMiCrO

So, calculating: N2 = sqrt(**0.25**) * **100** = **50** loops at 111mm each.

Now comparing:

- N1 = 111 x 100 = 11,100mm.
- N2 = 111 x 50 = 5,550mm.

For Half Wave: N2 = sqrt(0.5) * 100 = 70.71 loops at 111mm each.

- N2 = 111 x 70.71 = 7,848.81mm.

For Three Quarter Wave: N2 = sqrt(0.75) * 100 = 86.6 loops at 111mm each.

- N2 = 111 x 86.6 = 9,612.6mm.

Now, if we look at the length of the wire:

- 11,100 / 2 = 5,550mm = 1/4 wave, which is what we calculated for N2.

Respectively, we can get:

- 11,100 / 1.414 = 7,848 = 1/2 wave.
- 11,100 / 1.154 = 9,612 = 3/4 wave.

The Frequency ( **f** ) = 27.00 MHz

The Speed of Light ( **c** ) = 299,792,458 meters per second

We know, for an Antenna, a Half Wave is the optimum Wavelength to transfer Electromagnetic Energy, this is: **λ / 2**

Where

- Lambda (
**λ** ) = the Wavelength at Resonance.

Which means:

- Lambda (
**λ** ) = Speed of Light ( **c** ) / Frequency ( **f** ).
- Lambda (
**λ** ) = 299,792,458 / 27,000,000 = 11,103mm
- 11,103mm ≅
**N1**
- 11,103mm / 2 = 5,551mm
- 5,551mm ≅
**N2** calculated above ( **N2 = 111 x 50 = 5,550mm **)

Remember this:

This, in combination with our Antenna Theory threads, here and here, with the thread here and here, means we have a lot of very special logic to study!

The Coils become Resonant at the Half Wavelength, which is calculated by the Quarter Wavelength of **0.25**. This is using the Inductance, but means the Wire length of **N2** is half that of the **N1** as seen in the above Experiment, which is Lambda ( **λ** ) / **2**.

However, please remember, this is only one way, many ways exist to get to the same goal! We are specifically referring to Fighters work in this thread.

Chris