Extracting Energy with 'Diode-plug'

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  • Last Post 31 December 2022
baerndorfer posted this 09 November 2022

I like to show you a nice way how we can extract energy from coils which are in resonance. When we have our LC circuit and connect the load directly on the dipole the resonance went away because of some reason.

what we can do is using a diode-plug. this is how it looks like..

diode-plug_extractor

 

between the diodes and capacitors is a good amount of energy for powering our loads.

this is how it looks on my oscilloscope..

367

CH1 - this is the system input (pulsing circuit)

CH2 - diode-plug OUT(-)

CH3 - diode-plug OUT(+)

CH4 - resonating coil

i have good results with this so far.

hope someone find it useful too.

regards

 

 

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Chris posted this 10 November 2022

Hi Baerndorfer,

This is excellent work! Thanks for sharing!

Q: Did you want to add the term: "Diode-Plug" to the Title? It may make more sense to some?

Best Wishes My Friend,

   Chris

baerndorfer posted this 10 November 2022

i have to add some additional info to the diode-plug. this is from a document i found online. you can find this doc as attachment - i highly recommend reading it.

...

Here is where the fun starts, as we got RE in OU state. Now what do we do with it? Simply learn to extract it after you learn what it is! E gray defined it as cold electricity. I agree, it knocks standard minds out cold, as it has to be used differently than standard electricity, as load is defined only in amperes and not voltage. Voltage is at 90deg vectorial deviation of the current wave phasor, where current is maximal voltage is 0. Here tuning and RF knowledge becomes a must, as the term “antenna matching the DIPOLE” is in fact true.

Most loads are variable, so we need a system that remains OU while load varies (non-reflective power switching and transformation). The answer is a magnetic amplifier alike tuning (Old technology) or band-pass phase bridge, but that is for Extra class Amateur or FCC 1rst class Engineer (RF engineering). We have Full Value if we use as pulse AB type positive bias energy Pump (Switching) – see further.

The diode plug does that maintaining the OU condition but transferring the POTENTIAL to a capacitor that is discharged to transfer its POWER to a more standard co-phased PF=1 energy mode. The basic circuit: 2x C transverter circuit; each half equals basic LC at pure resonance, where the capacitor is tailored to the load at a logarithmic path 1.618 over input power raise. The circuit cycles as a constant turn on condition were OU manifests as energy rise within a Node V state (ZPE) resonance.

Energy is extracted by driving the capacitor to a load at the dead time (rest interval) where the other capacitor is being charged. As such we avoid LC field depletion. Discharged into a 0 resistance, the energy becomes infinite (theoretic). And not far from the truth, if this PULSE is used to SATURATE another LC as Electromagnetic Amplifier EASER pump (ON RV and LC Resonant circuits).
Related to Ferro-resonance, any Ferro-resonant transformer can be turned into a transverter diode PLUG, dividing capacitance by 2 and using each HALVE as a + - DC vector source. If SHORTED it just goes RESONANT, no burning in source.

The load R is to acquire the feel of the meaning of AMPERE LOAD, as in the current node the theoretical voltage = 0 as per ZERO POINT theory. C/2 = resonance as R = 0 Ohms; that means the 2 capacitors must be the same voltage but HALF the Farad value (C/2). In split C2X capacitor has the same value but (r/2) I/2 =P in half wave C=1x2/T (T=time) where the signal as AC = 2/120 second length at 1/30s time interval interlaced + - half C tank in opto-electronic trigger one half discharges non reflective to N load as the other logarithmically charges in radiant state in a perpetual "Turn on" cycling state. The capacitor energy is then defined in Joules Volt Ampere second discharge to N load C 2 x T -->N in push pull circuit.

RE-OU-v6_1 

Chris posted this 10 November 2022

Hey Baerndorfer,

I absolutely agree with this! This statement in particular:

OU manifests as energy rise within a Node V state (ZPE) resonance

 

This is a Golden Statement!

As the Node can be interpreted in many different ways, depending on the view point, V, I, B or even A Magnetic Vector, this Node, it is a High Energy State, high Pressure, or High Stress. 

Those before us have told us:

 

We see this in Experiment also:

 

It can be confirmed, the more Stress, the more Energy!

EDIT: I know you already know all this, but for others: 😉

Best Wishes

baerndorfer posted this 10 November 2022

this is how cold electricity looks like on the diodes...

report_20221110T104539 

 

Wistiti posted this 11 November 2022

I like to show you a nice way how we can extract energy from coils which are in resonance. When we have our LC circuit and connect the load directly on the dipole the resonance went away because of some reason.

what we can do is using a diode-plug. this is how it looks like..

diode-plug_extractor

 

between the diodes and capacitors is a good amount of energy for powering our loads.

this is how it looks on my oscilloscope..

367

CH1 - this is the system input (pulsing circuit)

CH2 - diode-plug OUT(-)

CH3 - diode-plug OUT(+)

CH4 - resonating coil

i have good results with this so far.

hope someone find it useful too.

regards

 

 

This is a really great findings!!!

Thanks you!!🌞

thaelin posted this 11 November 2022

   Considering this is Fr, what voltage are you driving this with? I have seen the d-plug for a long time but not in this flavor. This creates a very interesting scenario  and the use of external circuit to remove the excess at dead time. That remind me of Konehead's work. That makes it not reflect back to the source. 

   This may well be the way to run a motor off of reactive power and only use real to power the system. Will have to use UF Sic diodes as I doubt regular would stand up for long under that setup. 

thay

 

Jagau posted this 05 December 2022

Hi Bearn

In this experience by Avramneko and Zaev

It seems that the output current is 6 amps on A 5 but in the input 2 milliamps on A 3
difficult to explain this phenomenon.

 

Jagau

''Ether exists and its particles are those that keep the Universe in harmony and life in eternity, N.T. ''

Attached Files

baerndorfer posted this 27 December 2022

Screenshot from 2022-12-27 10-32-00

even in a simulated scenario we can have negative power present. the source (230V, 50Hz) is delivering reactive power to the capacitors. the loads are receiving real power (1.2W and 1.5W)

average consumption: -3.4W

 

bigmotherwhale posted this 27 December 2022

Did you ever look at the SERPS device? I built a replica of this, it returns power back to the source in a similar way to this but you can control it with software. 

https://patents.google.com/patent/US20170169941A1/en

 

baerndorfer posted this 31 December 2022

i did a bit of reading in the SERPS-papers you mentioned.

WOW

as far as i can see the idea is to have no magnetic force that acts against the primary source field. the logic behind is very similar to POC setup.

Screenshot from 2022-12-31 21-14-02

and we know how important it is, to switch at the right time (4 quadrants!) - we know this from negative-power-thread.

thank you bigmotherwale

 

bigmotherwhale posted this 31 December 2022

Exactly, This is what led me onto the POC devices.  Make sure the capacitors you use make the power factor zero, current and voltage out of phase) if you connect them to the transformer directly, and you should get good results. 

I built a half cycle replica, I can share design details and Arduino code if you want to have a play, this was a quick breadboard mock-up.

Dont forget I have mentioned Pavel Imris several times as well, his transformer is interesting to say the least. 

 https://patents.google.com/patent/DE202018004259U1/en

Kind Regards

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