Help needed in replication

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Fluktuacije posted this 1 weeks ago

Any feedback is welcome!

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Jagau posted this 1 weeks ago

Hi Fluk
Several here are able to help you but to fully understand what you are doing and to know what goal you want to achieve I need to have a schematic to fully understand, And maybe we can help you.
Welcome in this forum and thank you for sharing.
Jagau

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Fluktuacije posted this 1 weeks ago

OK thank you!

Here is the schematics:

 

 

I am trying to achieve the triangular waveform at the output (bucking). The two coils are 250 turns and are wound CW/ CCW and the primary is wound in the same direction as the coil underneath (the thick red wire). Bulb is 10W 12V. The scope shots are at the 0.1 ohm resistors. I've tried flipping the coils, changing polarity of diodes but this seems the best I can get... how do I get over 1 ?

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scalarpotential posted this 6 days ago

Dobar dan,

Try DC coupling on yellow trace, diode puts current in one direction

You can see the  voltage drop through the 0.1 ohm resistor to know the current, but you don't know the voltage drop through the light bulb and diode, try to show the voltage on those..

Jagau posted this 6 days ago

Hi Fluk
Thank you for your feedback, I understand better now.
This diagram is from Chris he can surely help you, he knows very well this circuit.
Jagau

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Fluktuacije posted this 6 days ago

Thanms guys! I don't know what dc coupling is but I've put a probe across the bulb instead of poc2. Short new video:

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scalarpotential posted this 6 days ago

Ok I'll give it a shot.

First make sure the diodes are connected exactly the same as in the diagram, if they are both reversed, they function as a fly-back diode (very educational video

), don't try combinations yet.


Set the scope to DC coupling (top right shows ac for yellow and dc for blue), look it up. AC coupling removes the DC offset, that's why the yellow signal is around 0v instead of above (see arrows at the left).
Put the probe to the positive of a component and the reference to the low voltage, so the polarity of the signal is shown correctly, blue signal is negative voltage, reverse the probes and it's the sane as the yellow. signal, both are on poc1 so they must be the similar in shape.

You do seem have a slope after the pulse dutycycle (horizontal part), but it is exponential decay instead of linear (maybe because of distributed ccapacitance?). See what happens when you lower the dutycycle.

 

 

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Chris posted this 6 days ago

Hi Fluktuacije,

Great work and Thank You for sharing!

I see you have several threads going, both similar:

 

We can help you! You are in the right place!

We have a thread: Builders Guide to Aboveunity Machines that contains all the information you need! However, in the mean time, the Exponential Curve you show:

 

This is wrong because you have the Polarity of one or more, of the Coils incorrect! You should see a linear Sawtooth Waveform

 

On the Input Side:

 

Now, what's going on here is the Coils Interactions are not correct. You need:

Each Coil has a job to do. Each Coil produces a series of Action Reaction Pairs.

The Actions are:

Action, Reaction and Counter-Reaction

 

So, the Input Coil Induces a Voltage on the Partnered Output Coil One, POnePOne then carry's a Current because it is Loaded. This is the Action, Input Coil, and the Reaction Secondary Coil.

The instant POne starts to Carry a Current, Partnered Output Coil Two, PTwo has an Induced Voltage because of this change in Current on POne, the Diode starts to Conduct and a Current Flows. This is the Counter-Reaction. The Current in PTwo must assist the Primary Current and also must Oppose POne.

 

The Arrangement is very simple, but it must be followed correctly to work, it does not make sense for many, but it works!

Now to make your machine go Above-Unity, you need to find Magnetic Resonance, and will need a larger core, larger Cross Sectional Area. The part marked Important, well, why is this important? 

Its the area that the Partnered Output Coils is made to be Resonant, this 10% Duty Cycle is your Input and your Input gets your Coils into Resonance. This means you need to tune your input to get the best from your Partnered Output Coils. The best analogy here is: Rotor Speed on your "Generator", this speed is a requirement, and needs to be at a specific speed for the Output to be sufficient. Too slow, output drops right off, too fast, too much voltage is generated and the "Generator" will fail if it is beyond the ratings! The Input Coil is your "Generators" Rotor Speed. You need to get this part right!

Your Input becomes reactive at Resonance, meaning all your Input is returned to your Input Source, battery, PSU or what ever, Power is returned. I have shown this in the Thread: The Input Coil.

This is very easy, but one needs to be attentive, have great attention to detail and follow precisely, what is required to succeed! All who deviate fail, none succeeds if they do not follow instruction! All who Succeed have followed precisely the requirements! All who Succeed have said how easy this is!

Best Wishes,

   Chris

P.S: Figuring out how to increase Output Voltage is Key! Its easy, so dont over think it!

Melendor posted this 5 days ago

Hello Fluktuacije,
Welcome to the forum.

Something is wrong with those waveforms...
I started the experiment 1 month ago and I have tried all combinations,  but I never had those waveforms...

That mosfet switch you have....does it work corectly ?

Take the signal generator....the mosfet and the Bulb....and switch the  bulb on and off with a Square.
Until what frequency the square wave remains Square? ...10 khz ...100 khz ?

If that works..disconnect the L3 completely.

If L1 and L2 are wound one above the other...same winding direction as you stated above ,

On the Triger (L1 coil ) ....You will have N on the left and S on the right.
On the            L2 Coil       You will have S on the left and N on the right.

Because you have placed a load on the L2 , Lenz Law is valid , and that is ""when a load is applied , the current in L2 will flow in such direction that will oppose the Coil that created it "

In this situation,you must place the diode on L2 , in such a way that it will allow the current to flow , in the proper direction of your new Transformer.

Use the right hand grip rule...and wrap your fingers in the direction of the winding....Your thumb will point out the direction of the Flux and the N pole.

It is not hard...You can do it.

I wish you good luck.
*Melendor the Wizard

Fluktuacije posted this 5 days ago

Chris, Scalarpotential and Melendor thank you very much for your feedback! You have given me a lot if info and guidelines. This might be a slow thread so please be patient as I try to execute all of the given. Will reply with a new video as I go through your suggestions. Thank you again!

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