Facts, keeping it Simple!

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Chris posted this 08 June 2019

My Friends,

Miss-Direction is present! We have not come this far to allow failure! Ask Simple questions, allow Solid Experiment to answer!

Input Coils need very Few Turns! Why?

Reactance is present in every Coil, the formula is: X = 2 Pi f L. The more Turns, the more Inductance ( L ) and it so happens, we can get the Inductance: L = X / 2 Pi f. Its a related equation. This means, Coils react very Slowly! The Higher the Inductance. Because the Reactance is deemed as a Resistance and measured in Ohms. So the total Coil Impedance: Z = R +j X.

Where:

  • j is the imaginary number √(-1)) + for Inductive, - for capacitive, from memory.
  • R = the DC Coil Resistance.
  • X = the Coil Reactance.

 

So we need Few Turns on the Input Coil, as I have shown from Day one:

 

I have been through so much information, and I get it is hard for others to catch up, but it is necessary! You need to read, study, learn, before you build!

More Turns are needed on the Output Coils, The Magnetic Fields must Buck, Oppose! Read the thread: Important: Delayed Conduction in Bucking Coils. This must be done in Magnetic Resonance, as I have tried to share with all here for so long! The Mr Preva Experiment is the best place to start, to see Magnetic Resonance.

I really want to encourage close study of the Threads I have posted! Without knowing the material, you're wasting your time trying to replicate! Study the Images I have shared!

 

 

 

Where D2 represents a Bi-Directional TVS.

 

 

Ref: Renesas Datasheet

 

Rise Time, determines how Fast the TVS Conducts! Rise over Run, where Run is Time! We have been through this many times also:

Where:

  • Rise is equivalent to the TVS VC.
  • Run is equivalent to the Time to Conduct.

 

Please, very close study of the scope shots, of the Waveforms, its required! Not optional! Please post questions, analysis, thoughts! It is all important!

The SI unit of Magnetomotive Force ( M.M.F ) is the Ampere-Turn ( AT ), and the CGS unit is Gilbert ( G ). So, Current ( I ) through Turns ( N ) is equivalent to the Magnetic Field!

When the Inductance is changed, Due to Magnetic Resonance, we have discussed this here: Non-Linear Inductance, then the Coils can do Work much longer, the Coils have a much longer period of Work. We have covered this in the Thread: Asymmetrical Regauging

As we have the Input Turn On, we have:

  1. Current ( I ) Through Turns ( N ) on the Input Coil changing in Time ( t ) - Positive Direction.
  2. Current ( I ) Through Turns ( N ) on the Output Coil changing in Time ( t ) - Negative Direction.
  3. Current ( I ) Through Turns ( N ) on the Output Coil changing in Time ( t ) - Positive Direction.

 

Point 3 occurs due to Delayed Conduction! Coupling Coefficient ( k ) is enough of a difference to allow for Induction, in Resonance, to occur. The Time Rate of Change between the two Magnetic Fields, Magnetic Resonance.

So, we have an equation that gives us a Total Magnetomotive Force of: 1 + -1 + 1 = 1

This means at Magnetic Resonance, we get no Negative Component, Lenz's Law is entirely Negated from Output to Input. An Above Unity Machine!

I urge the simple thinking, keeping things simple, for success. Don't forget, The MEG Falls into the same category as Tinman's RT, Grahams MIT, Don Smiths Resonant Energy Machines, and so on...

   Chris

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Jagau posted this 09 June 2019

Hi Chris


What is the voltage of the one direction TVS that you propose?

Jagau

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Chris posted this 09 June 2019

Hi Jagau,

Bi-Directional, Bi-Polar. AC.

   Chris

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Jagau posted this 10 June 2019

 

An excellent item to consult on TVS
their function and in what situation they are used
with detailed symbol

 

https://www.allaboutcircuits.com/technical-articles/transient-voltage-suppressors-tvs-an-introduction/

just for help

Jagau

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Vidura posted this 10 June 2019

Hey Chris,
I was thinking about do some tests for basic coil tuning to magnetic resonance, as in the suggested setup we have three coils, could it be convenient to tune first the two output coils tu achieve the correct interaction like in the mr Preva setup, and then proceed to add the input coil? Regarding the delayed conduction of one secondary, is the TVS component or switch necessary when we have equal inductance in both output coils only, in the mr Preva experiment the delay occurs due to the difference in the coils, am I correct with this?

Regards Vidura

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Chris posted this 10 June 2019

Hey Vidura,

I will do the best I can to answer below:

I was thinking about do some tests for basic coil tuning to magnetic resonance, as in the suggested setup we have three coils, could it be convenient to tune first the two output coils tu achieve the correct interaction like in the mr Preva setup, and then proceed to add the input coil?

 

Breaking the basic processes down to the smallest possible effects, we must observe, a very short Duty Cycle. Why? Well, lets take a look at the Input vs the Output:

 

 

Inside the Red Rectangle, at the Top we see Input, at the Bottom, we see only a small part of the Output. So, what's happening on the Output, when the Input is switched On?

What are the Coils doing, when the Input is Exciting the Coils? Why does such a small Duty Cycle on the Input create such a large Duty Cycle on the Output?

I strongly encourage a lot more study and discussion of the above scope shot and others like it that I have shared. This is so important!

 

What do we have? Well:

  1. Output Coils are Conductive almost from Input On to Output Off: Almost 100% Duty Cycle.
  2. Output M.M.F Direction: 1 + -1 = 0
  3. Input to Output M.M.F: 1 + -1 + 1 = 1
  4. While the Input is On, we have a very fast Rise Time!
  5. When the Input is turned Off, we have a Slow Linear Decay Time on the Output!
  6. The Rise Time of the Output is longer than the Input On Time!
  7.  M.M.F must be viewed as a Wave.
  8. A lot more...

 

Regarding the delayed conduction of one secondary, is the TVS component or switch necessary when we have equal inductance in both output coils only, in the mr Preva experiment the delay occurs due to the difference in the coils, am I correct with this?

 

A difficult question, I like to say anything is possible. But most of the time, a delay in the Conduction of one Output Coil is needed. But why? In the thread: Parallel Wire or Bifilar Coil Experiment I would like to think I covered pretty well why a delay in conduction is needed, but the Coupling Coefficient ( k ) was not really accounted for.

Yes in The Mr Preva Experiment, the Difference on Inductance with the Capacitor brings on Magnetic Resonance, equal and opposite Currents, 180 degrees apart. 

You see, we also have something else occurring, when we Delay Conduction, The Time Rate of Change of the Magnetic Fields ( B ) between each Coil, we get a larger Voltage, as shown above, so this, Delayed Conduction, has more effects going on than we might see initially.

NOTE: No# 5 above, this is Energy Being Pumped, after the Input is switched off:

 

So, I want to encourage, detailed discussion of the Waveforms shown, study and discuss, please...

   Chris

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Chris posted this 11 June 2019

My Friends,

We trick the Partnered Output Coils into Induction using Delayed Conduction. Because our Input is a Third Coil, this brings Asymmetrical Geometry to an otherwise Symmetrical process.

This Asymmetrical process can be viewed in the Waveform:

 

  • From the Green Arrow to the Red Arrow, Magnetic Compression is occurring, Magnetic Fields Oppose.
  • From the Red Arrow to the Blue Arrow, Input is off and the Two Output Coils are Pumping Current from Magnetic Field Collapse.

Both Points above are Pumping output Current! Both parts of the Cycle have active Output to the Load.

Question: From the Green Arrow to the Red Arrow, through what process, does the Input use less Current than normal?

   Chris

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Chris posted this 12 June 2019

My Friends,

A friend of mine sent me a PM, it appears there is a bit of Confusion still.

Simply, we are dealing with Electromagnetic Induction, Magnetically Resonant:

 

Each Force, Magnetomotive Force, works together in a resonant way. The M.M.F's one works against the Input, one works to assist the Input.

Answer: Mutual Inductance reduces the Input Current to a very low value, This acts as a Reactance in the Coil, and as a result, the Internal Impedance of the Input Coil increases, reducing the input Current to the Input Coil.

I hope this helps some!

   Chris

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